Info
Diese Frage ist geschlossen. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.
The code I am using ''idx'' is giving me wrong Voltage value.
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/902090/image.png)
The voltage is suppose to drop as I increase the temperature, but the ''idx'' selects the highest Voltage value in the vector. Is there way to reduce the Vpmax as the temperature increases?
Io = 0.1*10^(-9);
IL = 9.5;
V = linspace(0,0.691,100);
q = 1.6*10^(-19);
k = 1.380649*10^(-23);
% Temperature at 45°C and Irradiance of 900 W/m^2
T = 273.15+45;
G =700;
Gr = 1000;
I = (IL*(G./Gr))-(Io.*(exp((q.*V)./(k.*T))-1));
n = 72;
Vp = V.*n;
P = (I.*Vp);
[Pmax,idx] = max(P);
Imax = I(idx);
Vpmax = Vp(idx);
Isc = max(I);
Voc = max(Vp);
figure(8)
plot(Vp,P,'r','linewidth',2);
xlabel('Voltage (V)','fontsize',15);
ylabel('Power (W)','fontsize',15);
title('PV Panel PV Curve at 45°C 900 W/m^2','fontsize',15)
grid minor
axis([0,55,0,400])
figure(9)
plot(Vp,I,'k','linewidth',2);
xlabel ('Voltage [V]','fontsize',15);
ylabel ('Current [A]','fontsize',15);
title('PV Panel IV Curve at 45 °C 900W/m^2','fontsize',15)
yline(Imax)
xline(Vpmax)
text(Vpmax,Imax,['MPP=',num2str(Pmax),'[W]'])
grid minor
axis([0,55,0,9])
Any help will be greatly appreciated
1 Kommentar
Voss
am 22 Feb. 2022
idx, as calculated, is the index where P (Power) is at its maximum, not Voltage.
[Pmax,idx] = max(P); % idx: index of maximum Power
Also, temperature is a scalar constant, so I'm not sure why you say Voltage is a function of Temperature in this code. Can you please clarify?
Antworten (0)
Diese Frage ist geschlossen.
Siehe auch
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!