How can I graph the following parametric functions on a 3d graph?
6 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hi everyone! The three functions are as follows:
- x=r*cos(theta)sin(phi)
- y=r*sin(theta)sin(phi)
- z=4r
the three equations should make a hemisphere. This is what I have:
theta=[0:0.1:6.28];
phi=[0:0.1:6.28];
r=[0:0.1:2];
[THETA,PHI]=meshgrid(theta,phi);
X2=R.*cos(THETA).*sin(PHI);
Y2=R.*sin(THETA).*sin(PHI);
Z2=R.*cos(PHI);
mesh(X2,Y2,Z2)
I know that's obviously not right, but I don't know what to do to make it right. Any help would be appreciated! Thanks!
0 Kommentare
Antworten (2)
Marco Castelli
am 3 Dez. 2014
If R is a constant the code is:
theta=[0:0.1:6.28];
phi=[0:0.1:6.28];
R=2;
[THETA,PHI]=meshgrid(theta,phi);
X2=R.*cos(THETA).*sin(PHI);
Y2=R.*sin(THETA).*sin(PHI);
Z2=R.*cos(PHI);
mesh(X2,Y2,Z2)
In this case , if you want to see how the surface changes with r, you can use subplot to plot more picture in one window:
theta=[0:0.1:6.28];
phi=[0:0.1:6.28];
R=1;
[THETA,PHI]=meshgrid(theta,phi);
X1=R.*cos(THETA).*sin(PHI);
Y1=R.*sin(THETA).*sin(PHI);
Z1=R.*cos(PHI);
R=2;
[THETA,PHI]=meshgrid(theta,phi);
X2=R.*cos(THETA).*sin(PHI);
Y2=R.*sin(THETA).*sin(PHI);
Z2=R.*cos(PHI);
mesh(X2,Y2,Z2)
figure
hold on
subplot(1,2,1)
mesh(X1,Y1,Z1)
axis([-2 2 -2 2 -2 2])
subplot(1,2,2)
mesh(X2,Y2,Z2)
axis([-2 2 -2 2 -2 2])
0 Kommentare
Carlos Guerrero García
am 1 Dez. 2022
And...what about an animation?
[THETA,PHI]=meshgrid(0:2*pi/60:2*pi,0:pi/60:pi);
for R=0.1:0.01:2;
mesh(R.*cos(THETA).*sin(PHI),R.*sin(THETA).*sin(PHI),R.*cos(PHI));
title(['R=',num2str(R)]);
axis equal;
axis([-2 2 -2 2 -2 2]);
drawnow;
end
0 Kommentare
Siehe auch
Kategorien
Mehr zu Graphics Performance finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!