slicing a char array seems to internally allocate far more memory than expected
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My laptop has 64G ram.
I am reading a large text file (> 8G) with s=fileread(filename).
The resulting char array is
K>> whos('s')
Name Size Bytes Class Attributes
s 1x8656516488 17313032976 char
Grabbing everything but the first, e.g. 200 characters results in this:
K>> v = s(201:end);
Requested 8656516288x1 (64.5GB) array exceeds maximum array size preference. Creation of arrays greater than this limit may take a long time and cause MATLAB to become unresponsive.
See array size limit or preference panel for more information.
It seems that slicing a char array allocates 8x(number of chars). Is this expected?
[[Yes, I know of plenty of workarounds -- datastores, reading it pieces, fscanfs, etc., but this code is already a workaround to deal with the glacial speed of readtable(), so, I don't have to have it working, it's just somewhat surprising]]
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Sourav Karmakar
am 16 Feb. 2022
Hey Dmitri,
I've tried to create a char array of size 1x8656516488, but as it exceeds the maximum array size, it throws an error message. For example,
>> s = char(1:8656516488);
Requested 8656516488x1 (64.5GB) array exceeds maximum array size preference (48.0GB). This might cause
MATLAB to become unresponsive.
As you have 64G RAM , it should produce the same error. Try creating the 's' char array in your matlab workspace and check whether you are getting the same error message or not. Because, slicing only 200 chars from the array, does not change significantly in the memory( see difference between sizes of 's' and 'v' ).
You can refer to the following document for more reference:
Hope this helps!
1 Kommentar
Dmitry Kaplan
am 16 Feb. 2022
Bearbeitet: Dmitry Kaplan
am 16 Feb. 2022
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