i want to use if loop on a array. let say if i have two arrays:
a=[1 2 3 4 5]
b=[2 3 4 5 6]
now if i want to use if loop such that when any value in array 'a' is 3 and corresponding value in array 'b' is 4,it should print 'ali'.
i tried the following code but it did'nt work.
a=[3 4 3 44 3];
b=[4 3 4 34 26];
if (any(a==3) & b==4)
sprintf('ali')
end

 Akzeptierte Antwort

Image Analyst
Image Analyst am 10 Feb. 2022

0 Stimmen

Your parentheses are not right. Try it this way
a=[3 4 3 44 3];
b=[4 3 4 34 26];
if any(a==3 & b==4)
fprintf('ali\n')
end
ali
A=[1 2 5 66 7];
B=[6 4 4 77 8];
% if any element in array A is 5 and the corresponding B element is between 2 and 6
if any(A==5 & B>=2 & B<=6)
fprintf('ali')
else
fprintf('No Matches.\n')
end
ali

5 Kommentare

ali hassan
ali hassan am 10 Feb. 2022
@Image Analyst what if i want to know that how many times my first condition is fullfilled or you can say how many times it happened that:
% any element in array A is 5 and the corresponding B element is between 2 and 6
can it be done without using loop?
Image Analyst
Image Analyst am 10 Feb. 2022
The conditions are logical variables that can be converted to 0 or 1 when you do math on them. So to count the number of times in the vector where the condition is true, you can use sum
count = sum(A==5 & B>=2 & B<=6)
ali hassan
ali hassan am 11 Feb. 2022
@Image Analyst what if i want it to give logic 1 only if the condition satisfies for 5 times in a row. likewhat i mean is that it continuosly repeat for 5 times.
A=[1 5 5 5 5 5 6];
B=[6 2 5 5 4 3 5];
here only once it is happening that condiition is fulfilled five times in a row.
ali hassan
ali hassan am 11 Feb. 2022
here we have a vector column 'FF_liter_ho_'.If i want to know that how many times non zero values were greater than 770 in a row.
so it happened only once in the column.
@ali hassan if you have the Image Processing Toolbox, you can use regionprops():
ff_liter_ho = [nan, 75, 0, nan, nan, nan, nan, nan, nan, nan, 75, 37, nan, 0, 1, 2, 3, 4]
ff_liter_ho = 1×18
NaN 75 0 NaN NaN NaN NaN NaN NaN NaN 75 37 NaN 0 1 2 3 4
nonZeroIndexes = ff_liter_ho > 0
nonZeroIndexes = 1×18 logical array
0 1 0 0 0 0 0 0 0 0 1 1 0 0 1 1 1 1
props = regionprops(nonZeroIndexes, 'Area');
numRuns = length(props)
numRuns = 3
runLengths = [props.Area]
runLengths = 1×3
1 2 4

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

KSSV
KSSV am 7 Feb. 2022

0 Stimmen

a=[3 4 3 44 3];
b=[4 3 4 34 26];
if (any(a==3))
idx = a == 3 ;
if any(b(idx) == 4 )
fprintf('ali\n')
end
end

4 Kommentare

KSSV
KSSV am 7 Feb. 2022
what if i want to give a range of valus? like if a has a value between 3 and 4 and corresponding value of b is between 4 and 5?
KSSV
KSSV am 7 Feb. 2022
Any example data?
ali hassan
ali hassan am 10 Feb. 2022
assume, i have an array
A=[1 2 5 66 7] and B=[6 4 4 77 8]
i want to put if condition such that if any element in array A is 5 and the corresponding is between 2 and 6, i want to know how many times the condition meets.

Melden Sie sich an, um zu kommentieren.

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by