Could anyone help me with the interp1 please?
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
I have a system of two equations with two variables,I am using ode45 to solve the system numerically then trying to find Fisher Information(I),,Because my variables x(1) and x(2) depend on time so I am using '' interp1 '' ,,The problem is that I am not sure of using ' interp1' and the second thing I am getting two values for (I) while I am expecting to get only one value!
My code is :
function RunFisherpaperInt
A=1;
x0=[12 5];
dt=0.1;
tspan=0:dt:100;
b=4;
[t,x]=ode45(@Fisherpaper,tspan,x0,[],b);
x=[x(:,1),x(:,2)];
X = @(T) interp1(t,x,T) ;
a1=(15.*X(1)-b.*X(1).*X(2)) ;
b1=(-5.*X(1)+0.5.*X(1).*X(2)) ;
f = @(T) (A.*( (( a1.*( a1.*(15 - b.*X(2)) + b1.*(0.5.*X(2)) ) + b1 .*(a1.*(-b.*X(1)) +b1.*(-5 +
0.5.*X(2)) ) ).^2)./(a1.^2+b1.^2).^3 ) ) ;
I = integral(f,0,100,'ArrayValued',true)
1;
% function dxdt = Fisherpaper(t,x,b)
%x(1) = prey
% x(2) = predator
% dxdt=zeros(2,1);
% dxdt(1) = 15 * x(1) - b * x(1).* x(2);
% dxdt(2) = -5 * x(2) + .5 * x(1).* x(2);
% end
0 Kommentare
Antworten (0)
Siehe auch
Kategorien
Mehr zu Interpolation finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!