Answer from solver includes new variable z2

3 Ansichten (letzte 30 Tage)
Alexander
Alexander am 24 Nov. 2014
We use some equations to calculate the an initial pressure in an air chamber. Three equations that should not lead to redundancy.
Code:
syms P_air_initi
V_air_init = ((100000*V_airchamber^1.4)/P_air_initi)^(1/1.4);
x_airfront_init = V_air_init/A_airchamber;
eq6 = P_air_initi -(100000 + rho*g*(H_delivery-(H_airchamber-x_airfront_init))) ==0;
[sol] = solve(eq6,P_air_initi)
x_init = x_airfront_init; % Initial x in the air chamber
P_init = sol; % Initial pressure in air chamber
V_init = V_air_init; % Initial volume air in air chamber
Answer: sol =
(266194982560382061*pi + 1077543584708841800*z2)/(1099511627776*pi)
How do we get to the right solution? Thanks in advance for your effort, A

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