I have A=[1 3; 2 4]; and B=[5 6; 7 8];
I would like to create this two matrix line by line in C :
C=[1 3;5 6; 2 4; 7 8];

5 Kommentare

Sena Koçak
Sena Koçak am 1 Feb. 2022
By writing, C = [A(1,:);B(1,:);A(2,:);A(2,:)]
marwa hajji
marwa hajji am 1 Feb. 2022
great , but it is possible to use loop
Sena Koçak
Sena Koçak am 1 Feb. 2022
I wrote on my phone, so I hope there is error in that. There are simply two case, odd and even number of total row. Maybe there exists a simple solution, but it works :)
[sizeRowA sizeColA] = size(A); [sizeRowB sizeColB] = size(B);
C = zeros(sizeRowA + sizeRowB, sizeColA);
if (rem((sizeRowA + sizeRowB),2) == 0) for i = 1:((sizeRowA+sizeRowB)/2) C(2*i-1,:) = A(i,:); C(2*i,:) = B(i,:); end else for i = 1:((sizeRowA+sizeRowB-1)/2) C(2*i-1,:) = A(i,:); C(2*i,:) = B(i,:); end C(sizeRowA+sizeRowB,:) = A(sizeRowA,:) end
marwa hajji
marwa hajji am 2 Feb. 2022
thank you very much , yes exactly!!!!
Image Analyst
Image Analyst am 2 Feb. 2022
@marwa hajji did you see my Answer below (scroll down to the official Answers section, not up here in the comments section which is supposed to be used to ask the original poster for clarification)?

Melden Sie sich an, um zu kommentieren.

Antworten (2)

Benjamin Thompson
Benjamin Thompson am 1 Feb. 2022

0 Stimmen

A couple different ways:
>> A = [1 3; 2 4]
A =
1 3
2 4
>> B = [5 6; 7 8]
B =
5 6
7 8
>> C = A
C =
1 3
2 4
>> C = [C; B]
C =
1 3
2 4
5 6
7 8
>> C = [A; B]
C =
1 3
2 4
5 6
7 8

1 Kommentar

This
C =
1 3
2 4
5 6
7 8
is not what he wanted. He said he wants
C=[1 3;5 6; 2 4; 7 8]
C = 4×2
1 3 5 6 2 4 7 8

Melden Sie sich an, um zu kommentieren.

Image Analyst
Image Analyst am 1 Feb. 2022

0 Stimmen

Try this:
A=[1 3; 2 4]
A = 2×2
1 3 2 4
B=[5 6; 7 8]
B = 2×2
5 6 7 8
% What is desired:
C = [1 3;5 6; 2 4; 7 8]
C = 4×2
1 3 5 6 2 4 7 8
% My code
C2 = [A(1,:); B(1, :); A(2,:); B(2,:)]
C2 = 4×2
1 3 5 6 2 4 7 8
If you need it generalized to interleave a different number of rows than 2, or if A and B might have different numbers of rows, then it would be more complicated.

Kategorien

Gefragt:

am 1 Feb. 2022

Kommentiert:

am 2 Feb. 2022

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by