I have a random vector alpha with mean zero and standard deviation one, I want to find the expected value of alpha *alpha transpose
E[alpha*alpha']
0.0994
0.3661
-0.2125
0.2839

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VBBV
VBBV am 30 Jan. 2022

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alpha = [0.0994
0.3661
-0.2125
0.2839]
alpha = 4×1
0.0994 0.3661 -0.2125 0.2839
alpha.'
ans = 1×4
0.0994 0.3661 -0.2125 0.2839
E = alpha.*alpha.'
E = 4×4
0.0099 0.0364 -0.0211 0.0282 0.0364 0.1340 -0.0778 0.1039 -0.0211 -0.0778 0.0452 -0.0603 0.0282 0.1039 -0.0603 0.0806
Exp = mean(E) % expected value
Exp = 1×4
0.0133 0.0491 -0.0285 0.0381
Use mean function for your 4x4 matrix

2 Kommentare

rakesh kumar
rakesh kumar am 30 Jan. 2022
Dear VBBV,
I have read that if alpha is a random vector then Expectation of [alpha*transpose(alpha)] gives covariance matrix which in this case should be a 4 by 4 matrix. yours answer calucalate the mean of column vector.
VBBV
VBBV am 30 Jan. 2022
Bearbeitet: VBBV am 30 Jan. 2022
Refer this link for expected value.
You can evaluate covariance using expected value. But your question is related to expected value (which is obtained by taking mean of values ) and not that of covariance.

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KSSV
KSSV am 30 Jan. 2022

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a = [ 0.0994
0.3661
-0.2125
0.2839] ;
E = a'*a
E = 0.2697

1 Kommentar

rakesh kumar
rakesh kumar am 30 Jan. 2022
dear kssv i want to find the expected value of alpha* alpha transpose which is a matrix given below. I want the expected value of it.
alpha* alpha'= 0.0099 0.0364 -0.0211 0.0282
0.0364 0.1340 -0.0778 0.1039
-0.0211 -0.0778 0.0452 -0.0603
0.0282 0.1039 -0.0603 0.0806
>>

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