How to plot these equations ?

1 Ansicht (letzte 30 Tage)
Mohamed Ahmed
Mohamed Ahmed am 23 Jan. 2022
Kommentiert: Matt J am 23 Jan. 2022
Hello
I'm trying to plot these polynomials shown in the image, but I keep receiving errors and I'm not if my code is correct of not. Could you please help ?
regards
clear all
close all
clc
%%
Fs = 1000; % Sampling frequency
T = 1/Fs; % Sampling period
L = 1024; % Length of signal
t = 2*(0:L-1)*T; % Time vector
x = 0;
c = 1+i;
P(1) = 1;
Q(1) = 1;
P(2) = P(1) + exp(i*(2^(0))*t)*Q(1);
Q(2) = P(1) - exp(i*(2^(0))*t)*Q(1);
P(3) = P(2) + exp(i*(2^(1))*t)*Q(2);
Q(3) = P(2) - exp(i*(2^(1))*t)*Q(2);
P(4) = P(3) + exp(i*(2^(2))*t)*Q(3);
Q(4) = P(3) - exp(i*(2^(2))*t)*Q(3);
for m=1:16
x = x +c*exp(i*2*pi*m*t).*P(m);
end
figure
subplot(2,2,1)
plot(t,x)
title('signal')
  6 Kommentare
Matt J
Matt J am 23 Jan. 2022
That is correct. P(2) is a scalar location. It cannot hold a vector
Mohamed Ahmed
Mohamed Ahmed am 23 Jan. 2022

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Matt J
Matt J am 23 Jan. 2022
Bearbeitet: Matt J am 23 Jan. 2022
Change P(m) to P{m} and Q(m) to Q{m} everwhere.
Fs = 1000; % Sampling frequency
T = 1/Fs; % Sampling period
L = 1024; % Length of signal
t = 2*(0:L-1)*T; % Time vector
x = 0;
c = 1+i;
P{1} = 1;
Q{1} = 1;
for m=2:16
P{m} = P{m-1} + exp(1i*(2^(m-2))*t).*Q{m-1};
Q{m} = P{m-1} - exp(1i*(2^(m-2))*t).*Q{m-1};
end
for m=1:16
x = x +c*exp(1i*2*pi*m*t).*P{m};
end
whos x
Name Size Bytes Class Attributes x 1x1024 16384 double complex
  4 Kommentare
Mohamed Ahmed
Mohamed Ahmed am 23 Jan. 2022
Bearbeitet: Mohamed Ahmed am 23 Jan. 2022
Yes, It worked, I also plotted the magnitude and phase spectrum of the signal.
Is this plot considered a flat spectrum ?
Thank you :)
Matt J
Matt J am 23 Jan. 2022
I'm glad it worked, but please Accept click the answet to indicat so.
Whether it's to be considered flat is probably subjective...

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by