# Laplace transform not getting Value

1 view (last 30 days)
BEENA BASHEER on 16 Jan 2022
Answered: Walter Roberson on 16 Jan 2022
I tried to solve lapalce but not getting the value (Xs). Find the code below, Is there any issues in the code?
syms x(t) Xs
eqn = diff(x,t,2)+2*diff(x,t)+26*x(t) == 10*cos(t)*(heaviside(t-pi));
eqnLT = laplace(eqn)
eqnLT =
eqnLT = subs(eqnLT,laplace(x(t)), Xs);
eqnLT = subs(eqnLT, {x(0), diff(x(t), t, 0)}, {1/2,1});
Xs = solve(eqnLT, Xs)
Xs =

Star Strider on 16 Jan 2022
I do not see any specific problems.
syms x(t) Xs s
eqn = diff(x,t,2)+2*diff(x,t)+26*x(t) == 10*cos(t)*(heaviside(t-pi));
eqnLT = laplace(eqn)
eqnLT =
eqnLT = subs(eqnLT,laplace(x(t)), Xs);
eqnLT = subs(eqnLT, {x(0), diff(x(t), t, 0)}, {1/2,1})
eqnLT =
Xs = isolate(eqnLT, Xs)
Xs =
X(s) = rhs(Xs)
X(s) =
Perhaps the isolate function will do what you want.
.
Star Strider on 16 Jan 2022
As always, my pleasure!
.

Walter Roberson on 16 Jan 2022
syms x(t) Xs
eqn = diff(x,t,2)+2*diff(x,t)+26*x(t) == 10*cos(t)*(heaviside(t-pi));
eqnLT = laplace(eqn)
eqnLT =
eqnLT = subs(eqnLT,laplace(x(t)), Xs);
dx = diff(x,t);
eqnLT = subs(eqnLT, {x(0), dx(0)}, {1/2,1});
Xs = solve(eqnLT, Xs)
Xs =