reorder on a plot

vComplDire contains randomly on each cell one of these 4 directions:

DownRight; DownLeft; UpRight; UpLeft. (these are simply strings).

vComplDire is loaded by this for loop:

for i = 1:numel(vInterv)

if vbHori(i)

vComplDire{i} = 'Up';

else

vComplDire{i} = 'Down';

end

if vbVert(i)

vComplDire{i} = [vComplDire{i} 'Right'];

else

vComplDire{i} = [vComplDire{i} 'Left'];

end

end

boxplot(vInterv, vComplDire);

Boxplotting I get the graphic that I show on the attached pic.

I want to reorder the boxes on the graph like this:

1st DownLeft; 2nd DownRight; 3rd UpLeft; 4th UpRight.

I tried with "reorderlevels", "getlevels", etc... but no success.

Answer 1

[Voss]

% Generate random data. In order to be able to distinguish the boxes, make
% UpRight have mean 0, DownRight have mean 1, DownLeft have mean 2, and UpLeft have mean 3.
vInterv = randn(100,4)+[0 1 2 3];

vbHori = [true false false true];
vbVert = [true true false false];
vComplDire = cell(1,4);

for i = 1:4
    if vbHori(i)
        vComplDire{i} = 'Up';
    else
        vComplDire{i} = 'Down';
    end
    if vbVert(i)
        vComplDire{i} = [vComplDire{i} 'Right'];
    else
        vComplDire{i} = [vComplDire{i} 'Left'];
    end 
end
vComplDire

vComplDire = 1×4 cell array
    {'UpRight'}    {'DownRight'}    {'DownLeft'}    {'UpLeft'}

[~,idx] = ismember({'DownLeft','DownRight','UpLeft','UpRight'},vComplDire)

idx = 1×4

3 2 4 1

boxplot(vInterv(:,idx), vComplDire(idx));

[MR2022]

Thanks a lot!!

[Voss]

No problem! If this works, please mark the answer as accepted. Thanks!

[MR2022]

As you created it,

having "vInterv = randn(100,4)+[0 1 2 3]; ... etc."

your script works spotless. Fine.

But with my own data it doesn't work.

I probably should have included these details:

vInterv = 1x100 double

vbHori = 1x4 logical

vbVert = 1x4 logical

vComplDire = 1x100 cell (which will include these strings "DownLeft"... etc.)

vInterv has a value on each position, so "for i = 1:4" doesn't work.

I tried your code exactly this way:

for i = 1:numel(vInterv) % this nr. is 100

if vbHori(i)

vComplDire{i} = 'Up';

else

vComplDire{i} = 'Down';

end

if vbVert(i)

vComplDire{i} = [vComplDire{i} 'Right'];

else

vComplDire{i} = [vComplDire{i} 'Left'];

end

end

[~,idx] = ismember({'DownLeft','DownRight','UpLeft','UpRight'},vComplDire);

boxplot(vInterv(:,idx), vComplDire(idx));

[Voss]

When i == 5 you will get an error in the for loop because vbHori only has 4 elements.