plot the variable change

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shiv gaur
shiv gaur am 7 Jan. 2022
Kommentiert: shiv gaur am 7 Jan. 2022
pl plot dkx/dna=change in kx/change in na vs da value
any one pl help
function shiv7
%K0= (2*pi/1530)*1e6:(2*pi/10)*1e6:(2*pi/1630)*1e6;
%K0= linspace((2*pi/1530)*1e6,(2*pi/1630)*1e6,5);
%D1=1e-9:1e-9:3e-7;
D1= linspace(1e-9,3e-7,15);
for j=1:numel(D1)
da = D1(j);
p0 = 1;
p1 = 1.5;
p2 = 2;
TOL = 10^-8;
N0 = 100; format long
h1 = p1 - p0;
h2 = p2 - p1;
DELTA1 = (f(p1,da) - f(p0,da ))/h1;
DELTA2 = (f(p2,da ) - f(p1,da ))/h2;
d = (DELTA2 - DELTA1)/(h2 + h1);
i=3;
while i <= N0
b = DELTA2 + h2*d;
D = (b^2 - 4*f(p2,da )*d)^(1/2);
if abs(b-D) < abs(b+D)
E = b + D;
else
E = b - D;
end
h = -2*f(p2,da)/E;
p = p2 + h;
if abs(h) < TOL
disp(p)
break
end
p0 = p1;
p1 = p2;
p2 = p;
h1 = p1 - p0;
h2 = p2 - p1;
DELTA1 = (f(p1,da ) - f(p0,da ))/h1;
DELTA2 = (f(p2,da ) - f(p1,da ))/h2;
d = (DELTA2 - DELTA1)/(h2 + h1);
i=i+1;
end
%pv(j)=p;
P(j)=real(p)
%R(j)=real(r);
end
k0=2*pi/0.6328*10^-10;
plot(D1,P/k0)
end
function y=f(kx,da )
l=6330*(10)^(-10);
k0=2*pi/l;
nc=1.33;
ec=nc^2;
na=1.43;
ea=na^2;
nf=1.59;
ef=nf^2;
nm=0.064+1i*4;
em=nm^2;
ns=1.495;
es=ns^2;
df=0.5e-6;
dm=0.03e-6;
%da=0.06e-6;
%kx=(2*pi/l)*np*sin(a);
kc=sqrt(kx^2-ec*k0^2);
ka=sqrt(ea*k0^2-kx^2);
kf=sqrt(ef*k0^2-kx^2);
km=sqrt(em*k0^2-kx^2);
ks=sqrt(kx^2-es*k0^2);
rfm=(kf-km)/(kf+km);
rms=(km-ks)/(ks+km);
rfa=(kf-ka)/(kf+ka);
rac=(ka-kc)/(ka+kc);
a=(1-rfm)/(1+rfm);
b=(1-rms*exp(2*1i*dm*km))/(1+rms*exp(2*1i*dm*km));
c=(1-rfa)/(1+rfa);
f=(1-rac*exp(2*1i*da*ka))/(1+rac*exp(2*1i*da*ka));
pfms=2*atan(1i*a*b);
pfac=2*atan(1i*c*f);
y=2*kf*df-pfms-pfac;
end
  2 Kommentare
shiv gaur
shiv gaur am 7 Jan. 2022
pl plot between d(kx)/d(na) with respect with da is to be plot thanks for helping
shiv gaur
shiv gaur am 7 Jan. 2022
d(kx)/d(na)=d(kx)/d(da)/d(kx)/d(na)

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R2021b

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