for and if loop with two variables does not work

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Noush
Noush am 7 Jan. 2022
Kommentiert: Noush am 9 Jan. 2022
Hi,
I have an if and a for loop and I can't really figure out why it does not work. Can you tell my mistake? Basically I want to create the vector "Vektor2Batterie" with the conditions that I specified. The only reason I did not use "VektorBatterie" directly is because that also did not work, and I figured that might be the problem.
VektorBatterie = [A1 A8 A2 A9 A3 A10 A4 A11 A5 A12 A6 A13 A7 A14];
Vektor2Batterie = zeros(14,1)'
for i =1:14
for n = 2:2:14
if VektorBatterie(i) > 3040
Vektor2Batterie(i) = 3040;
if VektorBatterie(n) > VektorBatterie(n-1)
Vektor2Batterie(n) = VektorBatterie(n-1);
else
Vektor2Batterie(n) = VektorBatterie(i);
end
end
end
end
  3 Kommentare
Rik
Rik am 7 Jan. 2022
It looks like you want just 1 loop that will cap odd numbered positions to 3040 and ensures even numbered positions are smaller or equal to the previous element.
Can you confirm that is what you want?
Noush
Noush am 7 Jan. 2022
Yes thats exactly what I want!

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Akzeptierte Antwort

Walter Roberson
Walter Roberson am 7 Jan. 2022
VektorBatterie(1:2:end) = min(VektorBatterie(1:2:end), 3040);
VectorBattery(2:2:end) = min(VektorBatterie(2:2:end), VektorBatterie(1:2:end));

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