How to plot a 3D function?
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I'm trying solve this problem for the last one year but unable to do so. Please if anyone can help me.

I roughly code a program but don't know how can I plot it.
N0=100;
r_med=[0.445 0.889 1.445 2];
sigma_g=7;
N_ang=91;
theta=[10 20 45 60 90]/180*pi;
t = [0:180]/180*pi;
phi =0:(pi/360):(pi/2);
Num_r = 50e3;
r = linspace(1,50,Num_r)./2;
col=['k' 'b' 'r' 'g' 'm'];
I0=1;Q0=1;U0=0;V0=0;
for i=1:length(theta)
hold on
for j=1:length(r_med)
[P11(j,:),P12(j,:),P33(j,:),P34(j,:),Qsca_c(j,:),~,~] = ZK_W_Cloud_PhaseFunc(N0,r_med(j),sigma_g,N_ang);
[~,indx] = find(theta(i)==t);
F(j,:)=(P11(j,indx).*I0+((P12(j,indx).*Q0.*cos(theta(i)))+(P12(j,indx).*U0.*sin(theta(i)))));
end
end
3 Kommentare
Walter Roberson
am 31 Dez. 2021
never compare floating point numbers for equality unless they are derived from the same array. No promises that any theta entry will equal t.
John D'Errico
am 31 Dez. 2021
Your formula lacks any use of the parameter V0. So where is V0 employed?
Wiqas Ahmad
am 1 Jan. 2022
Antworten (0)
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