How to remove duplicate element from matrix ?

3 Ansichten (letzte 30 Tage)
Arshub
Arshub am 30 Dez. 2021
Kommentiert: Voss am 1 Jan. 2022
I have duplicate matrix S, I need remove the repeated elements from S, and
then put the absent numbers at the end to generate a new matrix X. iI implement remove duplicate element but how we add absent element at the end?
S=[1 11 1 4 3 14 6 11 13 11 7 15 5 9 9 7];
C=unique(S);

Akzeptierte Antwort

Voss
Voss am 30 Dez. 2021
Bearbeitet: Voss am 1 Jan. 2022
Here's one way:
S=[1 11 1 4 3 14 6 11 13 11 7 15 5 9 9 7]
S = 1×16
1 11 1 4 3 14 6 11 13 11 7 15 5 9 9 7
[C,i] = unique(S,'stable')
C = 1×11
1 11 4 3 14 6 13 7 15 5 9
i = 11×1
1 2 4 5 6 7 9 11 12 13
C = [C S(~ismember(1:numel(S),i))]
C = 1×16
1 11 4 3 14 6 13 7 15 5 9 1 11 11 9 7
  3 Kommentare
Arshub
Arshub am 31 Dez. 2021
Bearbeitet: Arshub am 31 Dez. 2021
@Benjamin can you help me in this state:
I need to use C=[1 3 4 5 6 7 9 11 13 14 15 1 7 9 11 11]
as index to perform permutation of matrix A =[111 222 30 4;50 65 70 83; 10 27 39 40 ; 54 67 72 81 ] by this method:
Substitute A(Ci ) with A (CM×N−i+1).
here i = 1, 2,..., M × N/2.
then i need to make reverse operartion to get the original matrix.
I write the code but when I make reverse operation I coulden't get the original matrix "M" after permutation, Why?
What should I do to get original matrix from permutated matrix?
Note: it is immportant to me use "Substitute A(Ci ) with A (CM×N−i+1)."
to permutate matrix.
%-----------------------------------------------------my rest of code ---------------------------------
A =[111 222 30 4;50 65 70 83; 10 27 39 40 ; 54 67 72 81 ];
[row,col]=size(A);
len=row*col;
A=reshape(A,1,len);
for i =1:len/2
A(C(i))=A(C(len-i+1));% Substitute A(Ci ) with A (CM×N−i+1)., permutation matrix
end
Ab=reshape(A,row,col)
AA=reshape(Ab,1,len);
for i =1:len/2
AA(C(len-i+1))=AA(C(i));% reverse Substitute A (CM×N−i+1) with A(Ci ) to get original matrix
end
AA=reshape(AA,row,col)
Voss
Voss am 1 Jan. 2022
@Arshub I modifed my answer after seeing DGM's comment on your other question. I believe this answer is more what this question is looking for.
I recommend you update that other question to clarify the relationship between S and C, specifically that:
S=[1 11 1 4 3 14 6 11 13 11 7 15 5 9 9 7];
[C,i] = unique(S,'stable');
C = [C S(~ismember(1:numel(S),i))];

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Produkte


Version

R2014a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by