I was getting an error message that conversion from cell to char is not possible. I showed in the next few lines how i stored the training images, also I crreated a imagedatastore for storing the images from folder for training and validation while the test images are in different folder.

 Akzeptierte Antwort

Voss
Voss am 28 Dez. 2021

0 Stimmen

It looks like Training_Image.Files is a cell array of chars, and you are attempting to take one of those chars and assign it to be a cell in a cell array (as opposed to assign it to be the contents of a cell in a cell array). You can do what I think you want to do in a couple of different ways:
files(h) = Training_Image.Files(n(h));
or
files{h} = Training_Image.Files{n(h)};
But then you're going to run into an error when h = 16 because n only has 15 elements.

Weitere Antworten (0)

Kategorien

Mehr zu Characters and Strings finden Sie in Hilfe-Center und File Exchange

Gefragt:

am 28 Dez. 2021

Kommentiert:

am 28 Dez. 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by