Using cellfun to extract specific rows from a cell array?

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omidm
omidm am 22 Dez. 2021
Kommentiert: omidm am 1 Apr. 2022
Hello,
I have a 1x6 cell array, 'Peaks':
Peaks = {199x4500} {192x4500} {167x4500} {171x1950} {157x1500} {191x1500}
I would like to create a new cell array, 'New_Peaks' using only 16 rows from each cell. The row numbers I want to choose are are in a 16X6 double array, 'Indices'.
Indices =
2 1 1 1 4 1
16 23 7 72 133 24
44 30 19 15 13 63
41 15 28 9 18 58
35 26 31 3 15 4
8 49 39 19 53 32
11 72 40 96 29 64
14 39 55 73 111 84
153 33 57 129 12 71
70 116 63 92 75 60
144 104 95 94 68 83
137 137 97 108 77 74
91 155 107 140 120 97
36 40 119 49 144 56
80 64 127 105 43 59
160 94 145 66 149 49
I tried the following line:
New_peaks = cellfun(@(x) x(Indices), all_peaks, 'UniformOutput', false)
But the output is a 1x6 cell array consisting of 16x6 doubles.
The output I want is:
New_peaks = {16x4500} {16x4500} {16x4500} {16x1950} {16x1500} {16x1500}
Is cellfun able to extract the contents of a cell array in this way?
  3 Kommentare
omidm
omidm am 22 Dez. 2021
Hi, sure, uploaded the 'peaks' and 'indices' variables.
the cyclist
the cyclist am 23 Dez. 2021
Separate piece of advice: Don't name a variable "peaks", which shadows the name of a function. That can cause issues and confusion.

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Matt J
Matt J am 22 Dez. 2021
Bearbeitet: Matt J am 23 Dez. 2021
New_peaks =cellfun(@(a,b) a(b,:), Peaks,num2cell(Indices,1) ,'uni',0);
  6 Kommentare
Matt J
Matt J am 1 Apr. 2022
Bearbeitet: Matt J am 1 Apr. 2022
In that case, you can just use Indices in its current form.
New_peaks =cellfun(@(a,b) a(b,:), Peaks,Indices ,'uni',0);
I would also encourage you to read the cellfun documentation to understand what this is doing.

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