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not compatible with the size

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SANDIPKUMAR ROYADHIKARI
SANDIPKUMAR ROYADHIKARI am 11 Dez. 2021
Kommentiert: Walter Roberson am 12 Dez. 2021
itr=0; % number of iteration
for t=1:1:3
itr=itr+1;
b(itr)=[sin(t) cos(t)];
end
In the above code , I am getting the error " Unable to perform assignment because the indices on the left side are not compatible with the size of the right side."
Please tell me how to fix.

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Chunru
Chunru am 11 Dez. 2021
itr=0; % number of iteration
for t=1:1:3
itr=itr+1;
b(itr, :)=[sin(t) cos(t)]; % Two numbers for each iteration form a row for a matrix b (nitr x 2)
end
b
b = 3×2
0.8415 0.5403 0.9093 -0.4161 0.1411 -0.9900
  4 Kommentare
Chunru
Chunru am 12 Dez. 2021
itr=0; % number of iteration
for t=1:1:3
itr=itr+1;
b(itr, :)=[sin(t) cos(t)];
c(itr, :)=[1-sin(t) 1];
end
d=[b c]
d = 3×4
0.8415 0.5403 0.1585 1.0000 0.9093 -0.4161 0.0907 1.0000 0.1411 -0.9900 0.8589 1.0000

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