how to use fzero is for loop?

1 Ansicht (letzte 30 Tage)
Dameon Solestro
Dameon Solestro am 11 Dez. 2021
Beantwortet: Dyuman Joshi am 11 Dez. 2021
Im trying to solve quadratic formulas in for-loop where the previous x value is needed for the next loop.
x(1)=10
for i=2:4
f=@(x) (x(i)^2)-(3*x(i)*(x(i-1)))-4
x(i)=fzero(f,0,[])
end
x'
Error using fzero>localFirstFcnEval (line 729)
FZERO cannot continue because user-supplied
function_handle ==> @(x)(x(i)^2)-(3*x(i)*(x(i-1)))-4
failed with the error below.
Index exceeds the number of array elements. Index
must not exceed 1.
Error in fzero (line 286)
fx = localFirstFcnEval(FunFcn,FunFcnIn,x,varargin{:});
Error in randnot (line 3)
x(i)=fzero(f,0,[])
Is there any way to fix this??

Antworten (1)

Dyuman Joshi
Dyuman Joshi am 11 Dez. 2021
How exactly will your f be defined if x(i) is not defined. Not sure what you want to do but, Try this -
x(1)=10;
for i=2:4
y=roots([1 -3*x(i-1) -4]);
x(i) = y(abs(y)==min(abs(y)));
end
x'
ans = 4×1
10.0000 -0.1327 1.8108 -0.6569

Kategorien

Mehr zu Optimization finden Sie in Help Center und File Exchange

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by