How can I transmit JPG file within in 8bit array for visible light communication

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I tried some progarm. but thre is some issue. How can I fix it? i need to transmit an image.
i=imread('Image.jpg');
R = i(:,:,1); %red
G = i(:,:,2); %green
B = i(:,:,3); %blue
for i=1:183
for j=1:275
R(i,j);
bin_Str = dec2bin(R(i,j));
C = reshape(bin_Str',1,numel(bin_Str));
D = reshape(C,size(bin_Str,2),size(bin_Str,1));
  2 Kommentare
Walter Roberson
Walter Roberson am 10 Dez. 2021
What is the point of your C and D? . For example intensity 13, dec2bin would be '1101'. Transpose gives
'1'
'1'
'0'
'1'
reshaping that to 1 row gives '1101' again, exactly what you already had. size('1101',2) is 4, and it has 1 row so D is reshape('1101',4,1) which gives the column vector again. What is the point??
Thakshila Dayani
Thakshila Dayani am 10 Dez. 2021
I havent idia about it. but I tried above code. I need to transmit image in led driver. and also the reciving part. how can i do it the best?

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Walter Roberson
Walter Roberson am 11 Dez. 2021
filename = 'flamingos.jpg';
img = imread(filename);
bitstream = reshape((dec2bin(img(:), 8) - '0').', 1, []);
reconstructed = uint8( reshape(bin2dec(reshape(char(bitstream + '0'), 8, []).'), size(img)) );
imshow(img);
title('original');
imshow(reconstructed);
title('reconstructed');
  7 Kommentare
Walter Roberson
Walter Roberson am 31 Jan. 2022
I would make the same recommendation for Arduino as for Raspberry Pi: send the entire bytes over the link, and have the destination break out the bits for transmission purpose. Write a bit of C or C++ code that will execute on the destination.

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