Find index in matrix

I am looking to find the first value in a 1600x6 dimension matrix. Column 1 contains dates formatted as yymmdd and column 2 has times formated as mmss.

How would I find the row that contains say 100104 1012 which would be 10:12 on Oct 04 2010

I just need the row index so I can collect the rest of the values

Answer 1

[David Young]

Assuming it's a numerical matrix, called M:

d = 100104;
t = 1012;
row = find(M(:,1) == d & M(:,2) == t)

If it's a cell matrix with strings, use strcmp(d, M(:,1)) etc. instead of ==.

Answer 2

[Andrei Bobrov]

[~,indrow] = ismember([101004,1012],A(:,1:2),'rows')