loop calculation and skipping the numbers
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YOGESHWARI PATEL
am 6 Dez. 2021
Kommentiert: Star Strider
am 8 Dez. 2021
d=20;
h=2;
g=9.8;
u=zeros(1)
v=zeros(1)
for x=[1 6 11 16 21 ]
for t=[1 6 11 16 21 26 31]
u(x,t)=h*sqrt(g/d)*(sech((sqrt(3*h/4*d^3))*(((x-1)/10)-(sqrt(g/d)*(1+(h/2*d))*((t-1)/10)))))^2;
v(x,t)=h*(sech((sqrt(3*h/4*d^3))*((x-1/10)-(sqrt(g/d)*(1+(h/2*d))*(t-1/10)))))^2;
end
end
disp(u)
disp(v)
I use this code to evaluate the value of u and v at different x and t .I want to skip the values so i wish this code .But all the values are not displayed.
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Akzeptierte Antwort
Star Strider
am 6 Dez. 2021
The indexing is incorrect. It leaves gaps. The gaps can be eliminated with a more efficient indexing approach.
This fixes that problem, however other problems may remain.
d=20;
h=2;
g=9.8;
% u=zeros(1)
% v=zeros(1)
xv=[1 6 11 16 21 ];
tv=[1 6 11 16 21 26 31];
u = NaN(numel(xv), numel(tv));
v = NaN(numel(xv), numel(tv));
for k1 = 1:numel(xv)
x = xv(k1);
for k2 = 1:numel(tv)
t = tv(k2);
u(k1,k2)=h*sqrt(g/d)*(sech((sqrt(3*h/4*d^3))*(((x-1)/10)-(sqrt(g/d)*(1+(h/2*d))*((t-1)/10)))))^2;
v(k1,k2)=h*(sech((sqrt(3*h/4*d^3))*((x-1/10)-(sqrt(g/d)*(1+(h/2*d))*(t-1/10)))))^2;
end
end
disp(u)
disp(v)
.
2 Kommentare
Star Strider
am 8 Dez. 2021
Preallocating the matrices, then referencing the variables as elements of the original variable vectors.
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