Find the different elements in a cell array

Hi to all,

i have a problem because i have a cell array and i need to find the cells that contain both numbers 1 and 2.

Thanks.

Answer 1

[Stephen23]

Where out is your cell array:

fnh = @(v) any(v(:)==1)&&any(v(:)==2);
idx = cellfun(fnh,out)

[LL]

It gave me error of invalid expression for the fnh line.

[Stephen23]

@Lidia Frizzi: fixed now, please try it again.

[LL]

it works thank you!!!!

[LL]

@Stephen sorry could i please ask you, how can i find all the cell without the number 2?

[Stephen23]

fnh = @(v) all(v(:)~=2);

[LL]

Perfect!!!

Now i have a matrix with only 1 (when the condition is true) and 0; but if i would like to maintain in the true cells the contents of the initial cell array? how could i do this?

[Stephen23]

What should the output array contain for the false indices?

[LL]

Maybe 0

[Stephen23]

you could replace the cells in the existing cell array:

out(~idx) = {0};

or create a new cell array:

new = num2cell(idx);
new(idx) = out(idx)

[LL]

@Stephen i still need your help pls.

I have one cell array like this one, what i like to do, is to merge the contents of neighboring cells, other than zero.

[Stephen23]

@Lidia Frizzi: please show the expected result of that "merging".

[LL]

So for example in the rows 6-7 and colums 8-9 i have three cells not empty the result that i would like to obtain is like this.