Cells and Matrix division
9 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hi,
I have a problem where I want to find the solution to A*x=B
Where A is a matrix of 4x4 where each element in the matrix is of the size 1x10. B is a matrix 4x1 where each element is of the size 1x10. The x matrix should be a matrix 4x1 where each element is of the size 4x1 where each element is the size of 1x10. How can I succed with this?
If needed I can write a code with exemples of the matrices.
2 Kommentare
Antworten (2)
DGM
am 22 Nov. 2021
Bearbeitet: DGM
am 22 Nov. 2021
I'm still assuming you're using cell arrays, since that's the only way that the description makes sense.
I'm sure someone can whip up a more elegant solution, maybe even directly dealing with the cell array without converting it. ... but this is what I did as a simplified example.
sa = 4; % size of system
nsys = 10; % number of systems
% generate a test array (all coefficient matrixes)
A = repmat(randi([-100 100],sa,sa),[1 1 nsys]);
% rearrange to mimic the array you have
A = cellfun(@(x) permute(x,[1 3 2]),num2cell(A,3),'uniform',false)
% turn it back into a regular array
A = cell2mat(cellfun(@(x) permute(x,[1 3 2]),A,'uniform',false))
% all b vectors as you describe
b = repmat({repmat(10,[1 nsys])},[sa 1]);
% turn it into a regular array
b = cell2mat(b)
x = zeros(sa,nsys);
for k = 1:nsys
x(:,k) = A(:,:,k)\b(:,k);
end
x % the answers
% turn it back into an unweildy cell array??
x = num2cell(x,2)
0 Kommentare
Siehe auch
Kategorien
Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!