Plotting trajectory in 2D

How come this code is not resulting in a plot of the trajectory at varying angles?

function [x , y] = trajectory(Vo,O,t,g)

% Function for varying angle

x = Vo * cos(O) * t ;

y = Vo*(sin(O)*t)-(0.5*g*(t.^2));

g = 9.8;

Vo = 10;

t = (0:1:5);

for O = (0: (pi/8): pi);

[x,y] = trajectory(Vo,O,t,g);

end

plot (x,y);

hold on

end

Answer 1

[Nick]

Inside your function you are calling your function.You are also redefining the parameters you are sending to your function Vo, t inside the function

There might be more efficient ways but one way you could do this is take the for loop out of the function and your function would compute and plot x and y every call

      function [x , y] = trajectory(Vo,O,t,g)
        % Function for varying angle
        x = Vo * cos(O) * t ;
        y = Vo*(sin(O)*t)-(0.5*g*(t.^2));
        plot (x,y);
        hold on
      end

then in order to call this function use

 for O = (0: (pi/8): pi);
          [x,y] = trajectory(10,O,[0:1:5],9.8);
     end

if you want to keep that loop inside the function and just have a function call

function [x , y] = trajectory(Vo,t,g)
  % Function for varying angle
     for O = (0: (pi/8): pi);
        x = Vo * cos(O) * t ;
        y = Vo*(sin(O)*t)-(0.5*g*(t.^2));
        plot (x,y);
        hold on
    end
end

and to call it would be

[x,y] = trajectory(10,[0:1:5],9.8);

[Rildo]

Great answer, thanks.

[Phila Siffundza]

thank you, that really helped