Change elements by a set amount.

I have a vector that goes up in twos:

delta= 2 2 4 4 6 6

What function can I use so that:

delta= 2 2 3 3 4 4 ?

[Jay]

Hi Mischa,

for i = 1:u(1,1)
  if mod(delta(i,1),2) == 0    
    delta(i,1) = delta(i,1)
    %number is even    
  else
    delta(i,1) = delta(i+1,1)
    %number is odd    
  end
  delta= delta- delta/2 + 1
end

returns :

   2
   2
   2.0625
   2.09375
   2.125
   2.125

and not [2,2,3,3,4,4]

I have proceeded with some different code but the variable i does not update when the iteration runs through.

for i=1:6  
  %x_val = n
  if x_val ==n
    delta(i,1) = x_val
  else  %x_val~= n
    x_val = n
    delta(i,1) = x_val
  end
  % y_val to = x_val  
  if y_val==x_val
    delta(i+1,1) = y_val
  else
    y_val=x_val
    delta(i+1,1) = y_val
  end
  n=n+1
  i=i+2
end

prior to the end of the command i returns the value of 3 for the first iteration but for the second iteration it reverts back to the count 2.

[Image Analyst]

He didn't say to do all that stuff. You added code that broke it. Just do what he said. Like I did:

delta= [2 2 4 4 6 6]
delta = delta - delta/2 + 1

In the command window you'll see

delta =
     2     2     4     4     6     6
delta =
     2     2     3     3     4     4

exactly as you asked for. Of course since you didn't specify what algorithm was to be used, just simply that you wanted a function to return [2,2,3,3,4,4], I was going to suggest this function:

function delta = JustinsFunction(delta)
    delta = [2,2,3,3,4,4];

That also meets all your stated requirements, more than Mischa's actually because I actually created a function and he did not - he just used operators.

Answer 1

[Mischa Kim]

Justin, do you mean

 delta = delta - delta/2 + 1

?