how to remove the zeros from matrix x??
clear all
clc
n=1;
m=1;
z=randi([1 10],5,10)
for i=1:5
if(mod(i,2)==0)
for j=1:length(z)
if(mod(j,2)==0)
x(m,n)=z(i,j)
n=n+1;
end
end
m=m+1;
end
end

1 Kommentar

dpb
dpb am 19 Nov. 2021
Depends on what you mean by "remove". A matrix cannot be anything but a rectangular array, so you simply cannot "remove" elements leaving "holes" in a regular array. A cell array also has to be regular, but it does have the feature that a cell may contain the empty indicator. For a regular numeric array, you can use NaN or Inf as missing value indicators, but you can't not have something in every location.

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Antworten (1)

DGM
DGM am 20 Nov. 2021

0 Stimmen

If all you want is the intersection of all even rows and columns, just use indexing.
z = randi([1 10],5,10)
z = 5×10
2 7 1 1 2 5 2 6 8 4 1 5 1 4 8 10 1 9 2 9 9 3 5 8 6 6 6 6 5 8 2 2 3 1 8 3 1 9 3 5 4 1 1 8 8 5 6 6 5 7
x = z(2:2:end,2:2:end)
x = 2×5
5 4 10 9 9 2 1 3 9 5
FWIW, the reason your code doesn't work is because you never reset n

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am 19 Nov. 2021

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DGM
am 20 Nov. 2021

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