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xoring bits within a vector

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emad
emad am 14 Okt. 2014
Bearbeitet: emad am 14 Okt. 2014
hi every one.... i'm having a binary matrix with [101101110011 ; 100110110101 ; 011110011001 ; 111100010010] and i want to XOR bit1 with bit3 , bit4 with bit6, bit 7 with bit9, bit 10 with bit 12 for the whole matrix, i try to loop it but it didn't work... help needed
  1 Kommentar
Guillaume
Guillaume am 14 Okt. 2014
Is your matrix an n x 12 char array, a cell array of strings, or something else.
Assuming your matrix is called m, can you show the output of
whos m

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Akzeptierte Antwort

Thorsten
Thorsten am 14 Okt. 2014
Use space between the the 1's and 0's
M = [1 0 1 1 0 1 1 1 0 0 1 1 ; 1 0 0 1 1 0 1 1 0 1 0 1 ; 0 1 1 1 1 0 0 1 1 0 0 1 ; 1 1 1 1 0 0 0 1 0 0 1 0];
xor(M(:, 1:3:end), M(:, 3:3:end))
  1 Kommentar
emad
emad am 14 Okt. 2014
Bearbeitet: emad am 14 Okt. 2014
thanks Thorsten you save my day one more thing, what if i want to xor every three bits together?

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Weitere Antworten (2)

Guillaume
Guillaume am 14 Okt. 2014
Assuming your matrix is an n x 12 char array, and assuming bit 1 is the first bit on the left.
m = ['101101110011' ; '100110110101' ; '011110011001' ; '111100010010'];
mnum = m - '0'; %convert the strings into a matrix of 0/1 integers
mnxor = xor(mnum(:, [1 4 7 10]), mnum(:, [3 6 9 12])); %perform the xor. Change each array for specific bits.
mxor = char(mnxor + '0'); %convert back into a char array

emad
emad am 14 Okt. 2014
Bearbeitet: emad am 14 Okt. 2014
dear Guillaume thanks very much your code works very good...

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