Increasing precision when parsing float values using textread()

Hello,
I am using textread() function to parse text values; I have the following line which works well:
[V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11 V12 V13 V14] = textread(file_1,'%f %f %f %f %f %f %f %f %f %f %f %f %f %f','headerlines',5);
The problem I am facing is that float values in the original text contain 6 digits after decimal point, while textread() returns only 4 digits after the decimal point.
For example:
Original value: -0.785834
Value returned by textread(): -0.7858
Please, suggest how to get the full precision of floats when using textread()
Thanks in advance

1 Kommentar

Are you sure that the value returned is EXACTLY -0.7858, or is that just what matlab is displaying?

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 Akzeptierte Antwort

Stephen23
Stephen23 am 13 Okt. 2014
Bearbeitet: Stephen23 am 13 Okt. 2014
I just created a new text file containing only the text '0.1234567890123456789', and named it 'temp.txt'. Then I ran this:
>> A = textread('temp.txt','%f');
>> fprintf('%.20f\n',A)
0.12345678901234568000
This shows that textread has read that number up to the double precision limit (~17 sigfig).
The "problem" is likely to be how MATLAB displays numbers up to four decimal digits, much to the confusion of all MATLAB learners, who wonder where their digits have gone to. Don't worry, those digits are still there! Have a look at format for more information on how to change the displaying of numbers.
Also as Adam mentions, the documentation reccomends using textscan instead of textread.

1 Kommentar

Thanks, indeed the problem was with formatting when displaying the result!

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Weitere Antworten (1)

Adam
Adam am 13 Okt. 2014
Bearbeitet: Adam am 13 Okt. 2014
The help page (R2014b) suggests you should use textscan now instead of textread, but I assume the following works for either while textread still exists.
You can specify the precision you want for your floats by e.g.
%.6f
to specify the number of values after the decimal place.

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