How do I put annotation text pointing towards specific coordinate?

11 Ansichten (letzte 30 Tage)
Below is my code , I have tried to put annotation text pointing towards a coordinate(3.4, 4.8248) using trial and error method . What is the proper way ?
x=[1 2 2.5 3 4 5]
x = 1×6
1.0000 2.0000 2.5000 3.0000 4.0000 5.0000
y=[0 5 7 6.5 2 0]
y = 1×6
0 5.0000 7.0000 6.5000 2.0000 0
A=3.4;Lagrange(x,y,A)
A = 3.4000
s = 0
c = 1×2 cell array
{[3.4000]} {[4.8248]}
ans = 4.8248
function yint=Lagrange(x,y,xx)
A=3.4
n=length(x);
s=0
for i=1:n
product=y(i);
for j=1:n
if i~=j
product=product*(xx-x(j))/(x(i)-x(j));
end
end
s=s+product;
end
yint=s;
figure()
plot(x,y)
hold on
scatter(A,yint,"x","b")
scatter(x,y,"o")
title('Lagrange Interpolation'); xlabel('x'); ylabel('f(x)');
c={A yint}
annotation('textarrow',[0.7 0.6],[0.7 0.64],'String',c)
hold off
legend('Interpolated Function','Result Point f(3.4)','Given Data');
hold off
end

Akzeptierte Antwort

Matt J
Matt J am 9 Nov. 2021
Bearbeitet: Matt J am 10 Nov. 2021
x=[1 2 2.5 3 4 5];
y=[0 5 7 6.5 2 0];
A=3.4;Lagrange(x,y,A);
function yint=Lagrange(x,y,xx)
A=3.4;
n=length(x);
s=0;
for i=1:n
product=y(i);
for j=1:n
if i~=j
product=product*(xx-x(j))/(x(i)-x(j));
end
end
s=s+product;
end
yint=s;
figure()
plot(x,y)
hold on
scatter(A,yint,"x","b")
scatter(x,y,"o")
title('Lagrange Interpolation'); xlabel('x'); ylabel('f(x)');
c={A yint};
%%%%%Matt J added
ax=gca;
xl=xlim;
yl=ylim;
xy0=[xl(1),yl(1)];
Dxy=[diff(xl),diff(yl)];
fn=@(xy) (xy(:)'-xy0)./Dxy.*ax.InnerPosition([3,4])+ax.InnerPosition([1,2]);
p=fn([3.4, 4.8248]);
%%%%%%
annotation('textarrow',[0.7 p(1)],[0.7 p(2)],'String',c)
hold off
legend('Interpolated Function','Result Point f(3.4)','Given Data');
hold off
end

Weitere Antworten (1)

Sulaymon Eshkabilov
Sulaymon Eshkabilov am 9 Nov. 2021
Here you can use the values of c to place where you want your annotation to be displayed along with the arrow. E.g.:
...
c={A yint}
annotation('textarrow',[c{1,1}, c{1,1}-0.07*max(x)]/max(x),[c{1,2},c{1,2}-0.07*max(y)]/max(y),'String',c)
...
  3 Kommentare
Matt J
Matt J am 9 Nov. 2021
Sulaymon Eshkabilov's comment moved here
WIth the proposed solution, you don't need to find the coordinates by a trial and error. It takes up the found values of c. In other words, the annotation placement changes with respect to the calculated values of c.
Samson David Puthenpeedika
Samson David Puthenpeedika am 10 Nov. 2021
How to use values of c in the above code? When i tried values of 'c' it was giving error that values should be between 0-1

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