I want Estimate log to the base 10 value using 'x' number such that 10^estimated value is equal to or just exceeding x.

function [out] = log10_bywhile(x, inc)
esmt = 0;
if ~exist('inc','var')
	inc = 0.01;
end
inc1 = 0;
while esmt <=x
	esmt = 10^inc1;
	inc1 = inc1+inc;
end
out = inc1-inc;

This is the i wrote to calculate the estimated value for log10 but, for log10 of 100 I should be getting 2 as output as it is a perfect value.

>> log10_bywhile( 50, 0.1 ) % Correct output

ans =

    1.7000

>> log10_bywhile( 100, 1 ) % Wrong Output

ans =

     3

Answer 1

[Alan Stevens]

< not <=

a = log10_bywhile( 50, 0.1 )

a = 1.7000

b = log10_bywhile( 100, 1 )

b = 2

function [out] = log10_bywhile(x, inc)
esmt = 0;
% if ~exist('inc','var')
% 	inc = 0.01;
% end
inc1 = inc;

while esmt < x      %%%%%%%%%%%%%%%%%%  
	esmt = 10^inc1;
	inc1 = inc1+inc;  
end
out = inc1-inc;
end

[Manav Divekar]

Thank you! It was such a small logic 😅