Interpolating [3,3] matrix valued function using interp3

1 Ansicht (letzte 30 Tage)
memductance
memductance am 29 Okt. 2021
Beantwortet: Rishabh Singh am 5 Nov. 2021
Hello everyone
I have a [3,3] matrix valued function that I would like to interpolate using interp3 if that is possible. The sampled function is given in the form of a [N,N,N,3,3] matrix similar to the code sample below:
N=25;
coords=linspace(0,1,N);
[X,Y,Z]=meshgrid(coords,coords,coords);
values=zeros(N,N,N,3,3);
for i=1:1:N
for j=1:1:N
for k=1:1:N
values(i,j,k,:,:)=rand(3,3);
end
end
end
f=@(x,y,z) interp3(X,Y,Z,values,x,y,z);
f(0.5,0.5,0.5)
I'm not quite sure how I should go about using interp3 to interpolate said function?

Antworten (1)

Rishabh Singh
Rishabh Singh am 5 Nov. 2021
Since your matrix is 5-Dimensional you will have to use "interpn", and "ndgrid".
Below code should work, and provide you the required output.
N=25;
coords=linspace(0,1,N);
[X,Y,Z]=ndgrid(coords,coords,coords);
values=zeros(N,N,N,3,3);
for i=1:1:N
for j=1:1:N
for k=1:1:
values(i,j,k,:,:) = rand(3,3);
end
end
end
f=@(x,y,z) interpn(X,Y,Z,values,x,y,z);
output = squeeze(f(0.5,0.5,0.5))
Hope this helps.

Kategorien

Mehr zu Interpolation finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by