For loop and matrices w/ different elements?

I have the followling code which has values calculated that are inputs of two matrices A and B. The inputs are values that are calculated in a for loop of i=1:365 corresponding to 1 degree to 360 degrees. I need each value computed by dividing the matrices at each degree/iteration. Everything else works besides the matrix part. I am not including the portions of my code that calculate the inputs but know they are within the for loop
for i=1:360
%All my stuff getting the inputs of the matrices
A(i)=[1 0 1 0 0 0 0 0
0 1 0 1 0 0 0 0
-R12x(i) R12y(i) -R32y(i) R32x(i) 0 0 0 1
0 0 -1 0 1 0 0 0
0 0 0 -1 0 1 0 0
0 0 R23y(i) -R23x(i) -R43y(i) R43x(i) 0 0
0 0 0 0 -1 0 0 0
0 0 0 0 0 -1 1 0]
B(i)=[m2.*A2x(i)
m2.*A2y(i)
I2*a2
m3*A3x(i)
m3*A3y(i)
I3*a3(i)
m4*A4x(i)-F4x(i)
0];
F(i)=A(i).\B(i)
end

1 Kommentar

Buster
Buster am 27 Okt. 2021
i get the error -"Unable to perform assignment because the left and right sides have a different number of elements"

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 Akzeptierte Antwort

David Hill
David Hill am 27 Okt. 2021

0 Stimmen

B(i)=[m2.*A2x(i);
m2.*A2y(i);
I2*a2;
m3*A3x(i);
m3*A3y(i);
I3*a3(i);
m4*A4x(i)-F4x(i);
0];%need 8x1 matrix

5 Kommentare

Buster
Buster am 27 Okt. 2021
The equation is A*F=B where F is [8x1] and A=[8x8]. Im solving for F so could you elaborate on your answer a little bit? I apologize.
David Hill
David Hill am 27 Okt. 2021
B(i) needs to be a 8x1. If you do not put semicolons in or transpose, the way you have B(i) currently written is a 1x8 array.
Buster
Buster am 27 Okt. 2021
I did as you presented yet im still getting the error
"Unable to perform assignment because the indices on the left side are not compatible with the size of the right side."
Error (line 52)
A(i)=[1 0 1 0 0 0 0 0
Sorry, need to understand your variables. If you need to store all A matrices, you will need to make a 3-dimensional matrix.
A(:,:,i)=[1 0 1 0 0 0 0 0
0 1 0 1 0 0 0 0
-R12x(i) R12y(i) -R32y(i) R32x(i) 0 0 0 1
0 0 -1 0 1 0 0 0
0 0 0 -1 0 1 0 0
0 0 R23y(i) -R23x(i) -R43y(i) R43x(i) 0 0
0 0 0 0 -1 0 0 0
0 0 0 0 0 -1 1 0];
B(:,i)=[m2.*A2x(i);m2.*A2y(i);I2*a2;m3*A3x(i);m3*A3y(i);I3*a3(i);m4*A4x(i)-F4x(i);0];
F(:,i)=A(:,:,i)\B(:,i);
Buster
Buster am 27 Okt. 2021
Thank you so much

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am 27 Okt. 2021

Kommentiert:

am 27 Okt. 2021

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