Polyfit with centering and scaling values

7 Ansichten (letzte 30 Tage)
Raj Raj
Raj Raj am 3 Okt. 2014
Kommentiert: Raj Raj am 3 Okt. 2014
Hi All,
I want to output centering and scaling values from the command prompt.
Here is the sample data I took from the matlab help:
x = (0: 0.1: 2.5)';
y = erf(x);
When I tried polyfit command here is the result:
ppp = polyfit(x,y,3)
ppp =
9.284046212199847e-02 -6.231661786330390e-01 1.384345932284717e+00 -1.993673645226568e-02
Second trial with centering and scaling values as output requests gives
>> [ppp1,SSS,muu]= polyfit(x,y, 3)
ppp1 =
4.154044003296898e-02 -1.608834507201939e-01 2.001009389523068e-01 9.181275523715360e-01
SSS =
R: [4x4 double]
df: 22
normr: 3.578557910406126e-02
muu =
1.250000000000000e+00
7.648529270389177e-01
I just don't understand why the ppp is differing from ppp1.
Please let me know the mistake in my understanding... Thanks for your time.

Akzeptierte Antwort

Mohammad Abouali
Mohammad Abouali am 3 Okt. 2014
because ppp fits y to x
but ppp1 fits y to x^ where x^ = (x-mu1)./mu2;
check this code:
x = (0: 0.1: 2.5)';
y = erf(x);
ppp = polyfit(x,y,3)
ppp =
0.0928 -0.6232 1.3843 -0.0199
[ppp1,SSS,muu]= polyfit(x,y, 3)
ppp1 =
0.0415 -0.1609 0.2001 0.9181
plot(x,y,'r.')
hold on
plot(x,polyval(ppp,x))
plot(x,polyval(ppp1,x),'k')
plot(x,polyval(ppp1,(x-muu(1))./muu(2)),'g')
legend('Data','ppp','polyval(ppp1,x)','polyval(ppp1,(x-muu(1))./muu(2))');

Weitere Antworten (0)

Kategorien

Mehr zu Images finden Sie in Help Center und File Exchange

Tags

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by