How to display two vectors at the same time?

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Philip Chen
Philip Chen am 25 Okt. 2021
Kommentiert: DGM am 25 Okt. 2021
My code so far
x1=[0:1:10]
func=@(x1) 2*x1+9
x2=x1
func2=@(x2) 12-4*x2
total=[x1;func(x1)]
total2=[x2;func2(x2)]
plot(x1,func(x1))
hold on
plot(x2,func2(x2))
hold on
fprintf('(X=%5g Y=%5g)\n', total, total2)
fprintf('\n')
fprintf('(X2=%5g Y2=%5g)\n', total2)
My expected result:
(X= 0 Y= 9) (X2= 0 Y2= 12)
(X= 1 Y= 11) (X2= 1 Y2= 8)
(X= 2 Y= 13) (X2= 2 Y2= 4)
(X= 3 Y= 15) (X2= 3 Y2= 0)
(X= 4 Y= 17) (X2= 4 Y2= -4)
(X= 5 Y= 19) (X2= 5 Y2= -8)
(X= 6 Y= 21) (X2= 6 Y2= -12)
(X= 7 Y= 23) (X2= 7 Y2= -16)
(X= 8 Y= 25) (X2= 8 Y2= -20)
(X= 9 Y= 27) (X2= 9 Y2= -24)
(X= 10 Y= 29) (X2= 10 Y2= -28)
My actual result:
(X= 0 Y= 9) (X2= 1 Y2= 11)
(X= 2 Y= 13) (X2= 3 Y2= 15)
(X= 4 Y= 17) (X2= 5 Y2= 19)
(X= 6 Y= 21) (X2= 7 Y2= 23)
(X= 8 Y= 25) (X2= 9 Y2= 27)
(X= 10 Y= 29) (X2= 0 Y2= 12)
(X= 1 Y= 8) (X2= 2 Y2= 4)
(X= 3 Y= 0) (X2= 4 Y2= -4)
(X= 5 Y= -8) (X2= 6 Y2= -12)
(X= 7 Y= -16) (X2= 8 Y2= -20)
(X= 9 Y= -24) (X2= 10 Y2= -28)
What did I do wrong? How can I acheive this?
  1 Kommentar
DGM
DGM am 25 Okt. 2021
That's not what I get when I run the same code.
x1=[0:1:10];
func=@(x1) 2*x1+9;
x2=x1;
func2=@(x2) 12-4*x2;
total=[x1;func(x1)];
total2=[x2;func2(x2)];
fprintf('(X=%5g Y=%5g)\n', total, total2)
(X= 0 Y= 9) (X= 1 Y= 11) (X= 2 Y= 13) (X= 3 Y= 15) (X= 4 Y= 17) (X= 5 Y= 19) (X= 6 Y= 21) (X= 7 Y= 23) (X= 8 Y= 25) (X= 9 Y= 27) (X= 10 Y= 29) (X= 0 Y= 12) (X= 1 Y= 8) (X= 2 Y= 4) (X= 3 Y= 0) (X= 4 Y= -4) (X= 5 Y= -8) (X= 6 Y= -12) (X= 7 Y= -16) (X= 8 Y= -20) (X= 9 Y= -24) (X= 10 Y= -28)
fprintf('\n')
fprintf('(X2=%5g Y2=%5g)\n', total2)
(X2= 0 Y2= 12) (X2= 1 Y2= 8) (X2= 2 Y2= 4) (X2= 3 Y2= 0) (X2= 4 Y2= -4) (X2= 5 Y2= -8) (X2= 6 Y2= -12) (X2= 7 Y2= -16) (X2= 8 Y2= -20) (X2= 9 Y2= -24) (X2= 10 Y2= -28)

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