How to select non-sequential values in an array?
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Hello forum,
I am trying to select the first, fifth, and ninth values of a 12x1 matrix. I am aware of how to reference sequential values like a(1:5,1) for the first five values but cannot figure out how to properly reference the non-sequential values. Thank you!
1 Kommentar
ADITYA RAJ ANAND
am 2 Dez. 2020
a ( [1 , 5 , 9] )
added spacing for clear visibility, its optional !!
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Weitere Antworten (3)
Nestor Lora
am 30 Nov. 2019
49 Stimmen
ans = vector([1 5 9])
9 Kommentare
Aryan Ritwajeet Jha
am 17 Apr. 2020
This answer, is the first correct answer to the question. (Even if late by five years).
Tony Morrell
am 22 Apr. 2020
I'm doing the MATLAB Onrramp training which has the question how to do this without having explained it first, hence my search here. So, thanks for this answer.
Indices can be non-consecutive numbers. Try extracting the first, third, and sixth elements of density.
Carlos Mauricio Villamizar Mora
am 24 Apr. 2020
Hello, I'm also doing this the same course, I haven't find how to use variables as your index, can you help me?
Ben Vargas
am 2 Jun. 2020
I'm working on the same thing too! Nice!
m = density([1 3 6])
This will create a variable m that equals the first, third, and sixth element extracted from "density"
Sinhue Contreras Torres
am 21 Jun. 2020
I think it is the answer he was looking for. Thanks, i had the same trouble. Doing feedback i was missing the square brackets between parentheses. Now i know.
Walter Roberson
am 24 Jul. 2020
"This answer, is the first correct answer to the question."
Andrei's solution in 2014 was correct. Any information that is given in a Question is fair game for optimization.
Gaurav Ladha
am 27 Sep. 2020
Thanks for the answer. But I don't really understand the need of square brackets
Walter Roberson
am 27 Sep. 2020
Bearbeitet: Walter Roberson
am 30 Okt. 2020
vector(1 5 9) would be invalid syntax
vector(1, 5, 9) would try to refer to a single value at row 1, column 5, "page" 9.
[1 5 9] or [1, 5, 9] build a list with three elements, and passing the list in to vector() means to return one value for each entry in the list.
Why is [] used to construct lists and not something like %1, 5, 9% ? Well, you need a different character to mark the beginning and end of a list so that you can nest lists. They could have arbitrarily chosen something like #1, 5, 9% but it would not have been very readable. For readability they had to use one of the available paired delimiter characters, () or [] or {} or < > or /\ .
The () pair has a lot of history for use to indicate precidence, but there is some history of use to create "tuples" so it would not be completely ruled out, but it is easier to read code if you do not need to do careful bracket counting to determine if you are using precedence or tuples.
< > has been used to construct multidimensional objects in Maple, but even Maple uses [] for ordinary lists. Historically < > delimiters have been used to delineate formal syntax such as HTML and BNF. And it gets complicated to distinguish between using these as lists or using them as relationship operators.
{} does have some history of being used for lists, but it has more history of being used for sets.
/\ has no history that I know of of being used by anyone for lists, and it would have the complication of needing to be distinguished from division.
The pair that has the most history of being used for lists is [].
It is true that Mathworks could have chosen something else than [] to indicate lists, but [] has the greatest weight of history behind it, with {} perhaps being second and < > a distant third. Using () for lists is rare outside of formal textbook discussions of tuples, with the tuples discussed in such textbooks rarely being complex enough to require precedence grouping.
Mathworks using [] was not the only option, but it was the most natural choice.
Junaid Shaikh
am 29 Nov. 2020
Thanks, it works.
Li Zhou
am 25 Apr. 2020
21 Stimmen
density([1,3,6],1) if you are doing MATLAB Onramp
4 Kommentare
DEVESH YADAV
am 26 Apr. 2020
seriously competition is so damn tough , everybody is doing evevrything on planet earth
Likhitha Ramini
am 4 Mai 2020
density([1,3,6]) even this also works
Xiaodi Lin
am 24 Jul. 2020
It works, Thanks!
Irene Armenta
am 30 Okt. 2020
OMG thank you!
Adarsh Vijayan
am 27 Apr. 2020
Bearbeitet: Walter Roberson
am 24 Jul. 2020
for i=[1 3 6]
x=density(i)
disp(x)
end
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