How to grow a vector in a loop?
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Saurabh Tyagi
am 15 Okt. 2021
Kommentiert: Saurabh Tyagi
am 15 Okt. 2021
So I have two nested loops
for ii = 1:ldiv+1
for jj = 1:sdiv+1
x_m = sb_panel(ii,jj).xm;
y_m = sb_panel(ii,jj).ym;
z_m = sb_panel(ii,jj).zm;
for kk = 1:ldiv+1
for ll = 1:sdiv+1
x_a = sb_panel(kk,ll).xa;
y_a = sb_panel(kk,ll).ya;
z_a = sb_panel(kk,ll).za;
x_b = sb_panel(kk,ll).xb;
y_b = sb_panel(kk,ll).yb;
z_b = sb_panel(kk,ll).zb;
aa = 1/(((x_m-x_a)*(y_m-y_b)-(x_m-x_b)*(y_m-y_a)));
bb = ((x_b-x_a)*(x_m-x_a)+(y_b-y_a)*(y_m-y_a))/sqrt((x_m-x_a)^2+(y_m-y_a)^2);
cc = ((x_b-x_a)*(x_m-x_b)+(y_b-y_a)*(y_m-y_b))/sqrt((x_m-x_b)^2+(y_m-y_b)^2);
dd = (1/(y_a-y_m))*(1+(x_m-x_a)/sqrt((x_m-x_a)^2+(y_m-y_a)^2));
ee = (1/(y_b-y_m))*(1+(x_m-x_b)/sqrt((x_m-x_b)^2+(y_m-y_b)^2));
coeff = [(aa*(bb-cc)+dd-ee)];
end
end
end
end
The problem is the innermost loop runs as many times as it's supposed to and assigns the last value to 'coeff' but what I want is that each time it runs, it assigns a value to coeff, and then assign the value in next cell when it runs again.
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Akzeptierte Antwort
Matt J
am 15 Okt. 2021
Bearbeitet: Matt J
am 15 Okt. 2021
You could just vectorize everything.
x_m = [sb_panel.xm];
y_m = [sb_panel.ym];
z_m = [sb_panel.zm];
x_a = [sb_panel.xa].';
y_a = [sb_panel.ya].';
z_a = [sb_panel.za].';
x_b = [sb_panel.xb].';
y_b = [sb_panel.yb].';
z_b = [sb_panel.zb].';
aa = 1./(((x_m-x_a).*(y_m-y_b)-(x_m-x_b).*(y_m-y_a)));
bb = ((x_b-x_a).*(x_m-x_a)+(y_b-y_a).*(y_m-y_a))./sqrt((x_m-x_a).^2+(y_m-y_a).^2);
cc = ((x_b-x_a).*(x_m-x_b)+(y_b-y_a).*(y_m-y_b))./sqrt((x_m-x_b).^2+(y_m-y_b).^2);
dd = (1./(y_a-y_m)).*(1+(x_m-x_a)./sqrt((x_m-x_a).^2+(y_m-y_a).^2));
ee = (1./(y_b-y_m)).*(1+(x_m-x_b)./sqrt((x_m-x_b).^2+(y_m-y_b).^2));
coeff = reshape( aa.*(bb-cc)+dd-ee , [],1);
2 Kommentare
Matt J
am 15 Okt. 2021
Can you point out my mistakes
In your original approach? My other answer describes how to get that to work.
and more insight into what you did?
we first collected the fields of your stucture into vectors
s(1).a=10; s(2).a=20; s(3).a=30;
v=[s.a]
Then, you just use implicit expansion for all the arithmetic operations, e.g.,
v+(1:4).'
Weitere Antworten (2)
Scott MacKenzie
am 15 Okt. 2021
One approach is to declare coeff as an empty array before the first for-statement:
coeff = [];
then add new values to the end of the coeff array as follows:
coeff = [coeff, (aa*(bb-cc)+dd-ee)];
2 Kommentare
Scott MacKenzie
am 15 Okt. 2021
In that case, just reverse the order in the assignment:
coeff = [(aa*(bb-cc)+dd-ee), coeff];
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