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mean without stable step

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Fani
Fani am 25 Sep. 2014
Beantwortet: Fani am 25 Sep. 2014
Hi all! I need your help please!
my data are 3033 lines and 2005 columns. I want to find the mean for all columns separately but the step in lines is different. For example, i want to find the mean for the first 167 lines, then from 168 to 294, 295 to 428 and so on. what code can i write?
Thank you!

Akzeptierte Antwort

Fani
Fani am 25 Sep. 2014
This works perfect!!!
Thank you very much for your time!!!

Weitere Antworten (3)

Mikhail
Mikhail am 25 Sep. 2014
You can write a=mean(M,2) - this will find mean of matrix M along each column. And then take only values you need. For 3033*2005 this is ok.
  2 Kommentare
Mikhail
Mikhail am 25 Sep. 2014
Sorry, for columns use a=mean(M), or a=mean(M,1)
Mikhail
Mikhail am 25 Sep. 2014
Otherwise you can do it with for loop

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Fani
Fani am 25 Sep. 2014
In the same column the step is different. For example, in the first column i want to find mean for the first 167 lines, then from 168 to 294,295 to 459 and so on. And this for all columns.
  1 Kommentar
Mikhail
Mikhail am 25 Sep. 2014
ok, so you create vector containing number of lines you want to take: a=[1:167,168...].
If you want to take into account only this lines for all columns, you can make new matrix: N=M(a,:). The new matrix contains only lines you need. And use mean.

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Fani
Fani am 25 Sep. 2014
if i do this, i take mean for all these lines. I would like to take mean for 1:167, other mean for lines 168:294 and so on.

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