# i need code for small project

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Marwan Tayfour on 11 Oct 2021
Answered: Image Analyst on 11 Oct 2021
if x= sin t
x=sin 2t
t=0 :pi/2:pi:3*pi/2:2*pi:5*pi/2:3*pi7*pi/2:4*pi
i need the diagram
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### Answers (2)

Image Analyst on 11 Oct 2021
I don't even know what that means. Please use more words to explain, and maybe attach a diagram that you think it should look like.
You have to define both t and x before you do "if x=sin t" and the proper way would be
if x == sin(t)
but even that is not good since they're floating point numbers so you should read the FAQ:
But anyway not sure what Diagram means, but did you try plot:
plot(t, x, 'b-.', 'LineWidth', 2, 'MarkerSize', 20);
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KSSV on 11 Oct 2021
t=0 :pi/2:pi:3*pi/2:2*pi:5*pi/2:3*pi/7*pi/2:4*pi ;
x1 = sin(t) ;
x2 = sin(2*t) ;
plot(t,x1,'r',t,x2,'b')
legend('sin(t)','sin(2t)')
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