Tricky formula with cumulative sum
5 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Peta
am 23 Sep. 2014
Kommentiert: Peta
am 24 Sep. 2014
I’m trying to calculate a ”standard deviation series” with a formula that involves a cumulative sum, but my matlab skills apparently aren’t sufficient to figure out how to type the formula in matlab.
The equation I want to write can be seen in step 5. Here: http://en.wikipedia.org/wiki/Rescaled_range
I have a vector “X” and a vector “u” and if I just use the cumulative sum command matlab doesn’t interpret the sum in the way I want it. This is how I want the calculation to look like:
Y(1) = ( X(1)-u(1) )^2
Y(2) = ( X(1)-u(2) )^2 + ( X(2)-u(2) )^2
Y(3) = ( X(1)-u(3) )^2 + ( X(2)-u(3) )^2+ ( X(3)-u(3) )^2
Y(4) = ( X(1)-u(4) )^2 + ( X(2)-u(4) )^2+ ( X(3)-u(4) )^2+ ( X(4)-u(4) )^2
….and so on
So in other words the calculation is increasing in size for each step and keeps X(1), X(2), X(3) and so on but only uses the most current value for “u” in each of the calculations.
This should be pretty simple right? How do I make it happen in matlab, any ideas?
Thanks
3 Kommentare
Akzeptierte Antwort
Roger Stafford
am 24 Sep. 2014
Bearbeitet: Roger Stafford
am 24 Sep. 2014
To use 'cumsum' you need to get the u's out of the squared expression. Let's assume X and u are row vectors.
Y = cumsum(X.^2)-2*cumsum(X).*u+(1:size(u,2)).*u.^2;
Weitere Antworten (1)
Star Strider
am 23 Sep. 2014
This seems to do what you want:
X = randi(20,1,10); % Create ‘X’
u = 1:10; % Create ‘u’
for k1 = 1:10
Y(k1) = sum((X(1:k1)-u(k1)).^2);
end
At least it produces the correct result (checked with manual calculation).
0 Kommentare
Siehe auch
Kategorien
Mehr zu Creating, Deleting, and Querying Graphics Objects finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!