# convert number to string but keep it the same as it is

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Locks am 19 Sep. 2014
Kommentiert: Star Strider am 20 Sep. 2014
Hi,
I have a Matrix containing different time series and I gave them numbers (2000001, 2000002,2000003 etc.) and I would like to convert this numbers into a string. If I use int2Str I get some Kind of matlab representation of this number, but this is not what I am looking for. What I need is at the end a vector as follows:
A=['2000001','2000002','2000003', etc.]
how can I achieve this by a automatic command?
regards
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### Akzeptierte Antwort

Star Strider am 19 Sep. 2014
In one line:
M = [2000001, 2000002,2000003];
S = strsplit(num2str(M));
produces:
S =
'2000001' '2000002' '2000003'
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Guillaume am 20 Sep. 2014
strsplit (and strjoin) were introduced in version 2013a, if I recall.
Star Strider am 20 Sep. 2014
I don’t remember when it arrived.
In its absence, this is as good as it gets:
S = cellstr(int2str(M(:)))
and produces:
S =
'2000001'
'2000002'
'2000003'

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### Weitere Antworten (2)

Youssef Khmou am 19 Sep. 2014
Bearbeitet: Youssef Khmou am 19 Sep. 2014
You can achieve that command using transformation from matrix to cells, if M is your matrix :
M=magic(10);
N=size(M);
B=mat2cell(num2str(M(:)),ones(N(1)*N(2),1));
B=reshape(B,N(1),N(2));
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Mikhail am 19 Sep. 2014
You can convert each number separetely in the for loop.
for i=1:numel(M)
out(:,i)=int2Str(M(i))
end
And you will have out - array of strings Code may have some errors - i didn't try to compile it
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Locks am 19 Sep. 2014
tis results in
222
000
000
000
000
000
123
but that is exactly what I whant to avoid

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