Convert logical values into numeric values

I have a cell array 20000 rows and 20 columns with logical values:
A={0 0 0 0 1 0...
0 0 1 0 0 0
1 0 0 0 0 0
0 1 0 0 0 0 ...}
And I would like to convert this array into numeric values of 1 and 0. Can someone help me? Thank you.

 Akzeptierte Antwort

Star Strider
Star Strider am 19 Aug. 2014

8 Stimmen

This works:
B = double(cell2mat(A));
The cell2mat call converts it from a cell to a logical array, and double converts it to a double array.

Weitere Antworten (3)

chaman lal dewangan
chaman lal dewangan am 13 Mär. 2018
Bearbeitet: chaman lal dewangan am 13 Mär. 2018

2 Stimmen

I wrote small code
for a=1:number of rows
for b=1:number of columns
if A(a,b)==true
new_matrix(a,b)=1;
else
new_matrix(a,b)=0;
end
end
end

2 Kommentare

James Tursa
James Tursa am 13 Mär. 2018
Bearbeitet: James Tursa am 13 Mär. 2018
This doesn't work either. Have you tried it?
??? Undefined function or method 'eq' for input arguments of type 'cell'.
for a=1:number of rows
for b=1:number of columns
if A{a,b}
new_matrix(a,b)=1;
else
new_matrix(a,b)=0;
end
end
end
That should work but it is maybe too complicated for you need.

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Jonathan Patao
Jonathan Patao am 12 Mär. 2018
Bearbeitet: Jonathan Patao am 13 Mär. 2018

0 Stimmen

Try this:
B = cell2mat(A).*1;

4 Kommentare

I just did. It doesn't work:
>> A = {1 0;0 1}
A =
[1] [0]
[0] [1]
>> B = A.*1;
Undefined operator '.*' for input arguments of type 'cell'.
@James —
Yours confirms my result:
A = {[1 0 1 1 0] == 1};
B = A.*1;
It throws the same error.
you're right, my fault. you need to convert from cell first. try:
B = cell2mat(A).*1;
Star Strider
Star Strider am 13 Mär. 2018
... duplicating my Answer!

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