I am getting an error as Function definitions are not permitted in this context.
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
vetri veeran
am 7 Aug. 2014
Bearbeitet: Star Strider
am 7 Aug. 2014
My code
function dydt = HH(t,y)
% Constants
ENa=55.17; % mv Na reversal potential
EK=-72.14; % mv K reversal potential
El=-49.42; % mv Leakage reversal potential
gbarNa=1.2; % mS/cm^2 Na conductance
gbarK=0.36; % mS/cm^2 K conductance
gbarl=0.003; % mS/cm^2 Leakage conductance
I = 0.1; %Applied Current
Cm = 0.01; %Membrane Capacitance
% Values set to equal input values
V = y(1);
n = y(2);
m = y(3);
h = y(4);
gNa=gbarNa*m^3*h;
gK=gbarK*n^4;
gl=gbarl;
INa=gNa*(V-ENa);
IK=gK*(V-EK);
Il=gl*(V-El);
dydt = [((1/Cm)*(I-(INa+IK+Il))); an(V)*(1-n)-bn(V)*n; am(V)*(1-m)-bm(V)*m; ah(V)*(1-h)-bh(V)*h];
function a=am(v) %Alpha for Variable m
a=0.1*(v+35)/(1-exp(-(v+35)/10));
end
function b=bm(v) %Beta for variable m
b=4.0*exp(-0.0556*(v+60));
end
function a=an(v)%Alpha for variable n
a=0.01*(v+50)/(1-exp(-(v+50)/10));
end
function b=bn(v) %Beta for variable n
b=0.125*exp(-(v+60)/80);
end
function a=ah(v) %Alpha value for variable h
a=0.07*exp(-0.05*(v+60));
end
function b =bh(v) %beta value for variable h
b=1/(1+exp(-(0.1)*(v+30)));
end
can somebody say the answer for this. Thanks in advance.
0 Kommentare
Akzeptierte Antwort
Star Strider
am 7 Aug. 2014
You have to save your entire function dydt = HH(t,y) as a separate function file named HH.m. Everything else should work then.
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Annotations finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!