Infinite number of inputs and outputs in lopp

R = 150;
C = 20.*10^-3;
t = [0; 1; 2; 3; 4 ;5]; 
for Vin = input("Enter input V: ")
Vout = Vin.*(1-(exp(1).^(-t./(R.*C))))
end

This is the code that I've written. It will take in only one input for Vin and thus display only one output for Vout.

I want to change the loop such that infinite number of inputs can be put in resulting in infinite outputs, and the output Vout can also be stored for each input value. Right now if I run the program a second time, the first Vin and Vout values are lost.

Answer 1

[Bryant Lash]

so if you want infinite, then a for loop isn't the way to do it. You want to do a while loop. You can do something like this:

Though to be clear this is jsut about the least efficient way to do this.

allVIn = zeros(0,0);
allVOut = zeros(0,0);
userExited = false;
disp('leave empty to exit');
while ~userExited
    userResponse = input("Enter input V: ");
    if isempty(userResponse); 
        userExited = true;
    else
        allVIn(end + 1,1) = userResponse;
        allVOut(end + 1,1) = userResponse.*(1-(exp(1).^(-t./(R.*C))));
    end
end