How to substitute one value in vector by vector?
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Premysl Stastny
am 23 Sep. 2021
Beantwortet: Matt J
am 23 Sep. 2021
Hello,
I have got a vectro x=(-1 1 -1 1) and I need to replace positions containing -1 for a vector (1 2 3) and positions containing 1 for a vector (3 2 1). so the result should be x=(1 2 3 3 2 1 1 2 3 3 2 1).
Could somebody help me?
Thanks a lot
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KSSV
am 23 Sep. 2021
Bearbeitet: KSSV
am 23 Sep. 2021
x=[-1 1 -1 1] ;
iwant = cell(1,length(x)) ;
for i = 1:length(x)
if x(i) == -1
iwant{i} = [1 2 3 ];
elseif x(i) == 1
iwant{i} = [3 2 1] ;
end
end
iwant = cell2mat(iwant)
%% No loop
% No loop
x=[-1 1 -1 1] ;
iwant = cell(1,length(x)) ;
iwant(x==1) = {[3 2 1]} ;
iwant(x==-1) = {[1 2 3]} ;
iwant = cell2mat(iwant)
Weitere Antworten (4)
Matt J
am 23 Sep. 2021
x=[-1 1 -1 1];
i=(x+3)/2;
V=[1 2 3;3 2 1].';
X=reshape( V(:,i) ,1,[])
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