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Converting a linear equation to decibel

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flanker989
flanker989 on 18 Sep 2021
Commented: Star Strider on 18 Sep 2021
I'm trying to convert a linear polar plot to decibel but I don't know how to proceed. Here is the original:
theta = 2*pi*linspace(0, 1, 30);
r = cos(theta/2).^2;
polar(theta, r, 'r-');
This is my progress so far:
theta = 2*pi*linspace(0, 1, 30);
r = 10*log10(abs(cos(theta/2).^2));
b = find(r(-40))
b == -40
b = b + 40
polardb(theta, r, -40, 'r-');
I don't know how to proceed.

Accepted Answer

Star Strider
Star Strider on 18 Sep 2021
The ‘theta’ vector likely needs to have more points, however that appears to be correct.
I use a slightly different approach here —
theta = 2*pi*linspace(0, 1, 30);
r = cos(theta/2).^2;
figure
polarplot(theta, r, 'r-')
title('r(\theta)')
figure
polarplot(theta, mag2db(r), 'r-')
title('r(\theta) (dB)')
rt = rticklabels;
rticklabels(cellfun(@(x)sprintf('%s dB',x),rt', 'Unif',0))
.
  2 Comments
Star Strider
Star Strider on 18 Sep 2021
My pleasure!
If my Answer helped you solve your problem, please Accept it!
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