Is the Abstract keyword needed to make a method abstract?

1 Ansicht (letzte 30 Tage)
per isakson
per isakson am 17 Sep. 2021
Kommentiert: per isakson am 18 Sep. 2021
Is this correct Matlab syntax
classdef MyClass
methods
outarg = my_method( this, inarg );
end
end
R2018b accepts it. Assuming this class definition is correct
  • is MyClass abstract?
  • is the method, my_method, abstract?
meta.class reports that .Abstract==false for both.
  1 Kommentar
per isakson
per isakson am 18 Sep. 2021
Bearbeitet: per isakson am 18 Sep. 2021
Addendum: "Run in R2021a" can't execute these lines in the question, since the class definition causes an error
meta_class = meta.class.fromName( 'MyClass' );
meta_class.Abstract
ans = logical
0
meta_class.MethodList(1).Name
ans = 'my_method'
meta_class.MethodList(1).Abstract
ans = logical
0

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Steven Lord
Steven Lord am 18 Sep. 2021
That is valid syntax, but not for making my_method an Abstract method. What you've written tells MATLAB that my_method is implemented in a separate file, not in the classdef file for MyClass.
See this documentation page for more information on how to declare a method as Abstract.
classdef MyClass
methods (Abstract)
outarg = my_method( this, inarg );
end
end
  1 Kommentar
per isakson
per isakson am 18 Sep. 2021
@Steven Lord, thank you for the answer. I had forgotten (I never use separate files).
However, that means that MyClass.m needs to be in a class folder named, @MyClass.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Debugging and Analysis finden Sie in Help Center und File Exchange

Produkte


Version

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by