Knowing the closed form solution of dx/dt = 2 sin 3t − 4x, how do I construct my Simulink?
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Angelica Belo
am 4 Sep. 2021
Kommentiert: Angelica Belo
am 5 Sep. 2021
By inputting the following code in Matlab,
syms x(t)
eqn = diff(x) == 2*sin(3*t) - 4*x;
S = dsolve(eqn,x(0) == 0)
The output would be,
S = (6*exp(-4*t))/25 - (2*cos(3*t + atan(4/3)))/5
I know that my Simulink should be constructed as:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/729159/image.png)
However I'm struggling to find how to construct the (2*cos(3*t + atan(4/3)))/5 using the two Sine waves.
I was thinking that both of their properties would be:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/729164/image.png)
But I'm currently not sure if this is correct.
Any help would be greatly appreciated thank you!
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Paul
am 4 Sep. 2021
So you need to express
-cos(3*t + atan(4/3))
as the sum of two sine waves. If you're allowed to make the amplitude of one of the sine waves zero, then we know that a -cos can be expressed in terms of single sin. Here's an example that you should be able to adapt to your problem
syms a
simplify(sin(a + 3*pi/2))
Once you relate "a" to your problem, you'll be able to implement sin(a + 3*pi/2) in one Sine block, and the other Sine block won't matter as long as its Amplitude parameter is zero.
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