Filter löschen
Filter löschen

Plotting a polynomial problem

2 Ansichten (letzte 30 Tage)
Josie
Josie am 31 Jul. 2014
Beantwortet: Star Strider am 31 Jul. 2014
Trying to plot this polynomial for different values of A but no luck so far.
M=linspace(-10,10,100);
g=10;
for A=0.1:0.1:0.9
D=-(A^2-A+1/3)*(((A-1/2)*M*g-0.25*A^2)/(2*M*((A-1/2)^2+1)+0.5*(A^2-A+1/3)))-0.5*A^2
plot(M,D)
hold all
end
legend('A=0.1','A=0.2','A=0.3','A=0.4','A=0.5','A=0.6','A=0.7','A=0.8','A=0.9')

Akzeptierte Antwort

Image Analyst
Image Analyst am 31 Jul. 2014
You forgot to use .* instead of *.
Corrected code:
workspace;
clc;
M=linspace(-10,10,100);
g=10;
lineColors = lines(9);
counter = 1;
for A=0.1:0.1:0.9
D = -(A^2-A+1/3) .* (((A-1/2)*M*g-0.25.*A^2) ./ (2*M*((A-1/2)^2+1)+0.5*(A^2-A+1/3)))-0.5*A^2
plot(M, D, 'LineWidth', 2, 'Color', lineColors(counter, :));
hold on
counter = counter + 1;
end
legend('A=0.1','A=0.2','A=0.3','A=0.4','A=0.5','A=0.6','A=0.7','A=0.8','A=0.9')
grid on;
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0 0 1 1]);

Weitere Antworten (1)

Star Strider
Star Strider am 31 Jul. 2014
I don’t understand what ‘no luck so far’ means (I can only assume that a plot of several parallel lines of dots wasn’t your desired result), but after ‘vectorising’ your code (the line that assigns ‘D’) it produces a much different plot than the one your code originally produced:
M=linspace(-10,10,100);
g=10;
for A=0.1:0.1:0.9
D=-(A^2-A+1/3).*(((A-1/2).*M.*g-0.25.*A.^2)./(2*M.*((A-1/2).^2+1)+0.5.*(A.^2-A+1/3)))-0.5*A.^2;
plot(M,D)
hold all
end
legend('A=0.1','A=0.2','A=0.3','A=0.4','A=0.5','A=0.6','A=0.7','A=0.8','A=0.9')
‘Vectorising’ produces element-by-element operations, rather than MATLAB’s default matrix operations. It requires using the ‘dot operator’ in front of multiplication, division, and exponentiation operators: (.*), (./), (.^).
(The only exception is the transpose operator ('), where (.') produces a simple transpose rather than the default complex conjugate transpose. I mention that for completeness. It doesn’t relate to your code.)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by