How to find the first date of each month in a datetime array?

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Doheon Lee
Doheon Lee am 27 Aug. 2021
Beantwortet: Campion Loong am 30 Aug. 2021
I have a datetime array as below, and I like to find the first date of each month in the array.
d = [ '14-Jan-2018'
'19-Jan-2018'
'22-Jan-2018'
'26-Jan-2018'
'04-Feb-2018'
'25-Feb-2018'
'09-Apr-2018'
'14-Apr-2018'
'20-Apr-2018'
'10-May-2018'
'21-May-2018'
'01-Jun-2018'
'07-Jun-2018'
'11-Jun-2018'
'11-Jul-2018'
'31-Jul-2018'
'05-Sep-2018'
'07-Sep-2018'
'08-Sep-2018'
'28-Sep-2018'
'29-Sep-2018'
'29-Oct-2018'
'07-Nov-2018'
'12-Nov-2018'
'21-Nov-2018'
'21-Nov-2018'
'03-Dec-2018'
'12-Dec-2018'
'03-Jan-2019'
'04-Jan-2019']
d = datetime(d)
The desired output is as below.
['14-Jan-2018'
'04-Feb-2018'
'09-Apr-2018'
'10-May-2018'
'01-Jun-2018'
'11-Jul-2018'
'05-Sep-2018'
'29-Oct-2018'
'07-Nov-2018'
'03-Dec-2018'
'03-Jan-2019'
]
At first, it seems easy, but only few moments later I realized that it is a way harder and it takes me days on this problem without progress.
Please hlep with this, and thank you so much in advance for any help.

Akzeptierte Antwort

dpb
dpb am 27 Aug. 2021
Bearbeitet: dpb am 27 Aug. 2021
firstDate=groupsummary(d,findgroups(year(d),month(d)),@min);
gives
>> firstDate
firstDate =
11×1 datetime array
14-Jan-2018
04-Feb-2018
09-Apr-2018
10-May-2018
01-Jun-2018
11-Jul-2018
05-Sep-2018
29-Oct-2018
07-Nov-2018
03-Dec-2018
03-Jan-2019
>>
  3 Kommentare
dpb
dpb am 29 Aug. 2021
Indeed. It often takes some time to realize the right way to go at some operations in MATLAB. The use of grouping variables here is the key instead of trying to compute differences individually from component pieces which I gather is probably what you had tried...
Doheon Lee
Doheon Lee am 30 Aug. 2021
yes, it is pretty hard to realize the right way to do. What I learned from you will solve many problems that I definitely encounter in the future. Once again, thank you so much for the help :)

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Weitere Antworten (1)

Campion Loong
Campion Loong am 30 Aug. 2021
Alternatively...
% dateshift all dates to beginning of the month, and find the indices of the first unique entry
[~,idx_first_month_date] = unique(dateshift(d,'start','month'));
% use the indices on your original datetime array
d(idx_first_month_date)
This yields the same result on your input:
ans =
11×1 datetime array
['14-Jan-2018'
'04-Feb-2018'
'09-Apr-2018'
'10-May-2018'
'01-Jun-2018'
'11-Jul-2018'
'05-Sep-2018'
'29-Oct-2018'
'07-Nov-2018'
'03-Dec-2018'
'03-Jan-2019'
]

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R2021a

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